Thursday, July 16, 2015

Circuits connected in Parallel

In a parallel circuit the voltage is the same for all elements and corresponding current is different.
                  
V = V_1 = V_2 = \ldots = V_n
hen expression for series component of resistor capacitor and inductor are given by

Resistors: 

The current in each individual resistor is found by Ohm's law. Factoring out the voltage gives
I_\mathrm{total} = V\left(\frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}\right).
To find the total resistance of all components, add the reciprocals of the resistances R_i of each component and take the reciprocal of the sum. Total resistance will always be less than the value of the smallest resistance:
A diagram of several resistors, side by side, both leads of each connected to the same wires.
\frac{1}{R_\mathrm{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}.
For only two resistors, the unreciprocated expression is reasonably simple:
R_\mathrm{total} = \frac{R_1R_2}{R_1+R_2} .
To find the current in a component with resistance R_i, use Ohm's law again:
I_i = \frac{V}{R_i}\,.
The components divide the current according to their reciprocal resistances, so, in the case of two resistors,
\frac{I_1}{I_2} = \frac{R_2}{R_1}.
 electrical conductance G is reciprocal to resistance, the expression for total conductance of a parallel circuit of resistors reads:
{G_\mathrm{total}} = {G_1} + {G_2} + \cdots + {G_n}.

Inductors:

Inductors follow the same law, in that the total inductance of non-coupled inductors in parallel is equal to the reciprocal of the sum of the reciprocals of their individual inductances:
A diagram of several inductors, side by side, both leads of each connected to the same wires.
\frac{1}{L_\mathrm{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \cdots + \frac{1}{L_n}.
If the inductors are situated in each other's magnetic fields, this approach is invalid due to mutual inductance. If the mutual inductance between two coils in parallel is M, the equivalent inductor is:
\frac{1}{L_\mathrm{total}} = \frac{L_1+L_2-2M}{L_1L_2-M^2 }
If L_1=L_2
 L_{total} = \frac{L+M}{2}

Capacitors:

The total capacitance of capacitors in parallel is equal to the sum of their individual capacitances:
A diagram of several capacitors, side by side, both leads of each connected to the same wires.
C_\mathrm{total} = C_1 + C_2 + \cdots + C_n.


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