Tuesday, September 1, 2015

What is digital electronics?

Digital electronics are those electronics systems that use a digital signal instead of an analog signal. Digital electronics are the most common representation of Boolean algebra and are the basis of all digital circuits.In digital electronics all values are expressed in terms of 0's and 1's combination.

Thursday, July 23, 2015

working of amplifier

Single Stage RC Coupled CE Amplifier

The figure shows a single stage CE amplifier. C1 and C3 are coupling capacitors, they are used for blocking the dc component and passing only ac part they also ensure that the dc basing conditions of the BJT remains unchanged even after input is applied. C2 is the bypass capacitor which increases the voltage gain and bypasses the R4 resistor for ac signals.

bjt application amplifier The BJT is biased in the active region using the necessary biasing components. The Q point is made stable in the active region of the transistor. When input is applied as shown below the base current starts to vary up and down, hence collector current also varies as IC = β × IB. Therefore voltage across R3 varies as the collector current is passing through it. Voltage across R3 is the amplified one and is 180° apart from the input signal. Thus voltage across R3 is coupled to the load and amplification has taken place. If the Q point is maintained to be at the centre of the load very less or no waveform distortion will take place. The voltage as well as current gain of the CE amplifier is high (gain is the factor by which the voltage of current increases from input to output). It is commonly used in radios and as low frequency voltage amplifier.
bjt amplifier
To further increase the gain multistage amplifiers are used. They are connected via capacitor, electrical transformer, R-L or directly coupled depending on the application. The overall gain is the product of gains of individual stages. Figure below shows a two stage CE amplifier. various parameters of CE amplifier are
DefinitionExpression (with emitter degeneration)Expression (without emitter degeneration, i.e., RE = 0)
Current gainA_{\text{i}} \triangleq \frac{i_{\text{out}} }{ i_{\text{in}} } \,\beta \,\beta
Voltage gainA_{\text{v}} \triangleq \frac{v_{\text{out}} }{ v_{\text{in}} } \,\begin{matrix}-\frac{ \beta R_{\text{C}} }{ r_{\pi} + ( \beta +1 ) R_{\text{E}} }\end{matrix}\,\approx-g_m R_{\text{C}}
Input impedancer_{\text{in}} \triangleq \frac{v_{\text{in}}}{i_{\text{in}}}\,r_{\pi} +( \beta +1 ) R_{\text{E}}\,r_{\pi}
Output impedancer_{\text{out}} \triangleq \frac{v_{\text{out}}}{i_{\text{out}}}\,R_{\text{C}}\,R_{\text{C}}

types of transistor amplifier


1. common Emitter amplifier
2. common Base amplifier
3. common Collector amplifier

COMMON-COLLECTOR CONFIGURATION 
 Since there is no phase reversal between the input and output circuits of a common-collector configuration, the feedback network does not need to provide a phase shift. However, since the voltage gain is less than unity and the power gain is low, the common-collector configuration is very seldom used in oscillator circuits.


COMMON-BASE CONFIGURATION
The power gain and voltage gain of the common-base configuration are high enough to give satisfactory operation in an oscillator circuit. The wide range between the input resistance and the output resistance make impedance matching slightly harder to achieve in the common-base circuit than in the common-emitter circuit. An advantage of the common-base configuration is that it exhibits better high-frequency response than does the common-emitter configuration.


COMMON-EMITTER CONFIGURATION 
The common-emitter configuration has high power gain and is used in low-frequency applications.For the energy which is fed back from the output to be in phase with the energy at the input, the feedback network of a common-emitter oscillator must provide a phase shift of approximately 180 degrees.

Advantages and Disadvantages of transistor amplifier


Advantages of CE amplifier:

  1. A common emitter amplifier is inverting and has low input impedance
  2. high output impedance 
  3. high voltage gain
  4. high current gain.


Disadvantages of CE amplifier: 
  1. 1. It has a high output resistance. 
  2. 2. It responds poorly to high frequencies. 
  3. 3. It has high thermal instabilities. 
  4. 4. It's voltage gain is very unstable.

Advantages of CB amplifier:
  1.  decent voltage amplifier, and current in is about equal to current out (actually current in is slightly greater than current out).
  2. The common base circuit works best as a current buffer. It can take an input current at a low input impedance, and deliver nearly that same current to a higher impedance output.

Disadvantages of CB amplifier:
  1. It requires two DC power sources to run this type of circuit.
  2. Measure another voltage between emitter (input) and Collector(output). 
  3. Compare voltage between Emitter and Base to see it is within the limit of transistor. 
  4. Common Base circuit mostly use on OSC circuit or matching circuit. It has less gain than CE type.
  5. amplification factor of common base amplifier is less less than common emitter amplifier.

    Advantages of CC amplifier:
    1. It has current gain but maintain voltage gain unchanged
    2. It has the lowest output impedance compare to other type amplifier
    3. It can be used for impedance matching between an amplifier stage with a high output impedance and an amplifier stage with a low input impedance.
    4.  When used like this it is sometimes called a buffer amp or isolation amp. 
    5. When placed between the the two stages it prevents the stage with the low input impedance from overloading the stage with the high output impedance.
    6. The Voltage gain of a common collector amp is at best slightly less than 1
    COMPARISON AMONG DIFFERENT TYPES OF AMPLIFIER:
      Common EmitterCommon CollectorCommon Base
      Voltage GainMediumLowHigh
      Current GainMediumHighLow
      Input ImpedanceMediumHighLow
      Output ImpedanceMediumLowHigh

      Sunday, July 19, 2015

      Resistor colour coding


      Application of network theorem


      • Both the methods are used to solve the complex network.
      • Norton's Theorem & Thevenin's Theorem are "Duals". 
      •  substitution theorem can be used in both linear and nonlinear circuits. For those nonlinear circuits that have a unique solution, we can use the substitution theorem in the equivalent transformation.
      • they can be applied to both ac and dc source.
      • For easy detemination of circuit parameter

      Conversion between thevienin circuit to norton circuit

      A Norton equivalent circuit is related to the Thevenin equivalent by the following:

      R_\mathrm{Th} = R_\mathrm{No} \!V_\mathrm{Th} = I_\mathrm{No} R_\mathrm{No} \!

      I_\mathrm{No} = V_\mathrm{Th} / R_\mathrm{Th}. \!
             
      Thevenin to Norton2.PNG

      Thevenin's theorem

      • Any linear electrical network with voltage and current sources and only resistances can be replaced at terminals A-B by an equivalent voltage source Vth in series connection with an equivalent resistance Rth.
      • This equivalent voltage Vth is the voltage obtained at terminals A-B of the network with terminals A-Bopen circuited.
      • This equivalent resistance Rth is the resistance obtained at terminals A-B of the network with all its independent current sources open circuited and all its independent voltage sources short circuited.
                                                      
      Any black box containing resistances only and voltage and current sources can be replaced to a Thévenin equivalent circuit consisting of an equivalent voltage source in series connection with an equivalent resistance.
      To calculate the equivalent circuit:
      1. Calculate the output voltage, VAB, when in open circuit condition (no load resistor—meaning infinite resistance). This is VTh.
      2. Calculate the output current, IAB, when the output terminals are short circuited (load resistance is 0). RTh equals VTh divided by this IAB.
      The equivalent circuit is a voltage source with voltage VTh in series with a resistance RTh.
      Step 2 could also be thought of as:
      a. Replace the independent voltage sources with short circuits, and independent current sources with open circuits.
      b. Calculate the resistance between terminals A and B. This is RTh.

      Reciprocity theorem

      the reciprocity theorem states that if an emf E in one branch of a reciprocal network produces a current I in another, then if the emf E is moved from the first to the second branch, it will cause the same current in the first branch, where the emf has been replaced by a short circuit.

      Norton's theorem

      • Any linear electrical network with voltage and current sources and only resistances can be replaced at terminals A-B by an equivalent current source INO in parallel connection with an equivalent resistance RNO.
      • This equivalent current INO is the current obtained at terminals A-B of the network with terminals A-B short circuited.
      • This equivalent resistance RNO is the resistance obtained at terminals A-B of the network with all its voltage sources short circuited and all its current sources open circuited.


                                                             text
      circuit containing resistances only and voltage and current sources can be replaced by an equivalent circuit consisting of an equivalent current source in parallel connection with an equivalent resistance.
      To find the equivalent,
      1. Find the Norton current INo. Calculate the output current, IAB, with a short circuit as the load (meaning 0 resistance between A and B). This is INo.
      2. Find the Norton resistance RNo. When there are no dependent sources (all current and voltage sources are independent), there are two methods of determining the Norton impedance RNo.
      • Calculate the output voltage, VAB, when in open circuit condition (i.e., no load resistor – meaning infinite load resistance). RNo equals this VAB divided by INo.

      Thursday, July 16, 2015

      Circuits connected in Parallel

      In a parallel circuit the voltage is the same for all elements and corresponding current is different.
                        
V = V_1 = V_2 = \ldots = V_n
      hen expression for series component of resistor capacitor and inductor are given by

      Resistors: 

      The current in each individual resistor is found by Ohm's law. Factoring out the voltage gives
      I_\mathrm{total} = V\left(\frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}\right).
      To find the total resistance of all components, add the reciprocals of the resistances R_i of each component and take the reciprocal of the sum. Total resistance will always be less than the value of the smallest resistance:
      A diagram of several resistors, side by side, both leads of each connected to the same wires.
      \frac{1}{R_\mathrm{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}.
      For only two resistors, the unreciprocated expression is reasonably simple:
      R_\mathrm{total} = \frac{R_1R_2}{R_1+R_2} .
      To find the current in a component with resistance R_i, use Ohm's law again:
      I_i = \frac{V}{R_i}\,.
      The components divide the current according to their reciprocal resistances, so, in the case of two resistors,
      \frac{I_1}{I_2} = \frac{R_2}{R_1}.
       electrical conductance G is reciprocal to resistance, the expression for total conductance of a parallel circuit of resistors reads:
      {G_\mathrm{total}} = {G_1} + {G_2} + \cdots + {G_n}.

      Inductors:

      Inductors follow the same law, in that the total inductance of non-coupled inductors in parallel is equal to the reciprocal of the sum of the reciprocals of their individual inductances:
      A diagram of several inductors, side by side, both leads of each connected to the same wires.
      \frac{1}{L_\mathrm{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \cdots + \frac{1}{L_n}.
      If the inductors are situated in each other's magnetic fields, this approach is invalid due to mutual inductance. If the mutual inductance between two coils in parallel is M, the equivalent inductor is:
      \frac{1}{L_\mathrm{total}} = \frac{L_1+L_2-2M}{L_1L_2-M^2 }
      If L_1=L_2
       L_{total} = \frac{L+M}{2}

      Capacitors:

      The total capacitance of capacitors in parallel is equal to the sum of their individual capacitances:
      A diagram of several capacitors, side by side, both leads of each connected to the same wires.
      C_\mathrm{total} = C_1 + C_2 + \cdots + C_n.


      Circuits connected in Series

       In a series circuit the current is the same for all elements and corresponding voltage is different.
                                                 
I = I_1 = I_2 = \dots = I_n
       Then expression for series component of resistor capacitor and inductor are given by

      Resistor:
                  The total resistance of resistors in series is equal to the sum of their individual resistances:

      R_\mathrm{total} = R_1 + R_2 + \cdots + R_n
                                           
                                This is a diagram of several resistors, connected end to end, with the same amount of current through each.
      Electrical conductance presents a reciprocal quantity to resistance. Total conductance of a series circuits of pure resistors, therefore, can be calculated from the following expression:
      \frac{1}{G_\mathrm{total}} = \frac{1}{G_1} + \frac{1}{G_2} + \cdots + \frac{1}{G_n}.
      For a special case of two resistors in series, the total conductance is equal to:
      G_{total} = \frac{G_1 G_2}{G_1+G_2}.
      Inductor:
                   In that the total inductance of non-coupled inductors in series is equal to the sum of their individual inductances:
      A diagram of several inductors, connected end to end, with the same amount of current going through each.
      L_\mathrm{total} = L_1 + L_2 + \cdots + L_n
       it is difficult to prevent adjacent inductors from influencing each other, as the magnetic field of one device couples with the windings of its neighbours. This influence is defined by the mutual inductance M.
       For three coils, there are six mutual inductances M_{12}M_{13}M_{23} and M_{21}M_{31} and M_{32}. There are also the three self-inductances of the three coils: M_{11}M_{22} and M_{33}.
      ThereforeL_\mathrm{total} = (M_{11} + M_{22} + M_{33}) + (M_{12} + M_{13} + M_{23}) + (M_{21} + M_{31} + M_{32})

      By reciprocity M_{ij} = M_{ji}
      Capacitor:
                 
       The total capacitance of capacitors in series is equal to the reciprocal of the sum of the reciprocals of their individual capacitances:
      A diagram of several capacitors, connected end to end, with the same amount of current going through each.
      \frac{1}{C_\mathrm{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \cdots + \frac{1}{C_n}.